Trevor Linden, a former player for the Vancouver Canucks, is 1.93 m tall. On a hockey card, he is 5.4 cm tall. What scale was used to print the hockey card?

scale  used to print the hockey card is 27/965

scale  used to print the hockey card in decimal  is 1/35.74

Step-by-step explanation:

we know that in scale problems

scale is used in drawing to enlarge or reduce size of object by a certain amount

scale = size of object in drawing/ actual size of object

Height of trevor = 1.93 m

we know that  1 m = 100 cm

Height of trevor in cm = 1.93 m*100 = 193 cm (actual size)

(this is done so that unit of measurement is same for card and trevor's height i.e cm)

Trevor's card on hockey card = 5.4 cm(size in drawing)

scale used = Trevor's card on hockey card /Height of trevor in cm

                    = 5.4/193 = 54/ 1930 = 27/965

scale  used to print the hockey card is 27/965

scale  used to print the hockey card in decimal  is 1/35.74

answer: 0,6

step-by-step explanation:

this would make it the y intercept.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.