A point is chosen at random in the circle. What percent of the time will the point be in the
shaded region?
Round to the nearest tenth of a percent.

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e

kjgfcvbjkl

step-by-step explanation:

sdfghjkl; vbnm,

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15