The revenue generated by the band is given by the expression 50x+150 Select all of the ordered pairs that are solutions to the inequality:

50x + 150y > 1500

(1, 10)

(10, 1)

(0, 10)

(40, 0)

(1, 10) and (40, 0)

Step-by-step explanation:

Given expression 50x+150

inequality is

50x + 150y > 1500

it means that if we plug value of x and y from given option in  50x+150 then it should be greater than 1500.

lets check for all the option

(1,10)

50*1 + 150*10 = 50+1500 = 1550

Since , 1550 is greater than 1500, (1,10) is the solution for the inequality given

(10, 1)

50*10 + 150*1 = 500+ 150 = 650

Since , 650 is less than 1500, (10,1) is not the solution for the inequality given

(0, 10)

50*0 + 150*10 = 0 + 1500 = 1500

Since , 1500 is equal to 1500 but not greater than 1500, (0,10) is not the solution for the inequality given

(40, 0)

50*40 + 150*0 = 2000 + 0 = 2000

Since , 200 is greater than 1500, (40,0) is the solution for the inequality given above.

Thus, from the given option there are two solution for 50x + 150y > 1500

(1, 10) and (40, 0)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0