Can someone solve this?

Step-by-step explanation:

1. The angle facing the given arcs is half their sum, so is (180 +116)/2 = 148°. Angle 1 is the supplement of this, ...

  angle 1 = 180° -148° = 32°

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2. Short arc WY is the supplement of 70°, Long arc WVY is the difference of that and 360°:

  arc WVY = 360° -(180° -70°) = 180°+70°

  arc WVY = 250° . . . . . matches choice C

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3. Call the point of intersection of the secants X. The rule for secants is ...

  (XA)(XC) = (XB)(XD)

So, the length XC is ...

  XC = (XB)(XD)/(XA) = 2.4

and ...

  AC = XA +XC = 3.2 +2.4 = 5.6 . . . . . matches choice D

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4. As in problem 3, the product of lengths from the point of secant intersection to the points of circle intersection is the same for both secants.

  (NQ)(NR) = (NP)(NS)

Substituting segment sums where necessary, we have ...

  NQ(NQ +QR) = NP(NP +PS)

Solving for PS, we have ...

  PS = NQ(NQ +QR)/NP - NP . . . . . matches choice A

i believe it is 0.1m because the measurement of 30.4m limits how precise you can be

you can only be as precise as the least precise measurement

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)