Square ABCD was translated using the rule (x, y) → (x – 4, y + 15) to form A'B'C'D'. What are the coordinates of point D in the pre-image if the coordinates of point D’ in the image are (9, –8)?

D = (13, - 23 )

Step-by-step explanation:

Given the translation rule

(x, y ) → (x - 4, y + 15 )

To go in the reverse direction, that is image to original, then, reverse the operations in the translation rule.

(x , y ) → (x + 4, y - 15 ) , thus

D'(9, - 8 ) → D(9 + 4, - 8 - 15 ) → D(13, - 23 )

the 3rd on is correct

step-by-step explanation:

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