Mathematics, 10.06.2020 20:57 johrenandez

HELPPP Lane has a gift card worth $300 for a local entertainment store. Movies cost $20 each and
newly released video games cost $50 each. In order to use the gift card, Lane must purchase at
least seven items. Which is a combination of movies and newly released video games that
Lane could purchase using his gift card?

A 01 movie and 6 video games

B2 movies and 4 video games

C6 movies and 5 video games

D8 movies and 1 video game

Answers: 1

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Answers

Answer from: Anderson0300

D) 8 movies and 1 video game

Step-by-step explanation:

We are given that Lane has a gift card worth $300 for a local entertainment store.

Cost of 1 movie = $20

Cost of 1 video game = $50

In order to use the gift card, Lane must purchase at least seven items

A) 01 movie and 6 video games

Cost of 1 movie = $20

Cost of 6 video game = $50 \times 6 = 300$

Total cost = 300+20 = 320

Since Lane has a gift card worth $300 , So Lane could not purchase 01 movie and 6 video games using his gift card

B) 2 movies and 4 video games

We are given that she must purchase at least seven items

So, She could not buy 2 movies and 4 video games

C)6 movies and 5 video games

Cost of 6 movie = $20 \times 6 =120$

Cost of 5 video game = $50 \times 5= 250$

Total cost = 250+120=370

Since Lane has a gift card worth $300 , So Lane could not purchase 06 movie and 5 video games using his gift card

D) 8 movies and 1 video game

Cost of 8 movie = $20 \times 8 =160$

Cost of 1 video game = 50

Total cost = 160+50=210

So, she could purchase 8 movies and 1 video game

Answer from: Quest

$a_1 = 1$ , and

$a_{n+1} = a_n + (n + 1)$ for $n \ge 1$

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote $a_1 = 1$ , $a_2 = 3$ , $a_3 = 6$ , so that we can call

1 the 1st term, 3 the 2nd term, 6 the 3rd term,etc.

note the following:

from the 1st term (1) to the 2nd term (3), we go up by 2,from the 2nd term (3) to the 3rd term (6), we go up by 3from the 3rd term (6) to the 4th term (10), we go up by 4, andfrom the 4th term (10) to the 5th term (15), we go up by 5.

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from $a_1 = 1$ , to get to $a_2 = 3$ , we add $2(=1+1)$

from $a_2 = 3$ , to get to $a_3 = 6$ , we add $3 (=2+1)$

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

$a_1 = 1$ , and $a_{n+1} = a_n +(n + 1)$ for $n \ge 1$

Answer from: Quest

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

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HELPPP Lane has a gift card worth $300 for a local entertainment store. Movies cost $20 each and