What is the standard equation of the circle in the graph

option 1

Step-by-step explanation:

formula:(x-h)^(2)*(y-k)^(2)=r^2

well if you move the circle 3 units left h is (-3), plug it in, you get 3, so it is (x+3)^2*(y-k)^(2)=r^2

if you move the circle 2 units up, plug it in you get (-2), so it is

(x+3)^2*(y-2)^(2)=r^2

now, the radius is 3 (we can see from the graph) so radius ^2 is 9, thus

(x+3)^2*(y-2)^(2)=9

this is the answer, and the option that has it is answer is option 1

i dont get the question

step-by-step explanation: