Point R has coordinates (-5, -7) and point T has coordinates (3,-3). Which point is located 1/4 of the distance from point R to point T?
Enter x-coordinate of the point here
and the y-
coordinate of the point here

  (x, y) = (-3, -6)

Step-by-step explanation:

The (x, y) distance from R to T is ...

  (Δx, Δy) = T - R = (3, -3) -(-5, -7) = (3 -(-5), -3 -(-7)) = (8, 4)

Then 1/4 of the distance is ...

  (Δx, Δy)/4 = (8, 4)/4 = (2, 1)

This is added to the R coordinates to find the desired point:

  point = R +(2, 1) = (-5, -7) +(2, 1) = (-5+2, -7+1) = (-3, -6)

The coordinates are ...

  x-coordinate: -3

  y-coordinate: -6

table 3 represents a direct variation function. : )

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!