How many zeroes are at the end of 10! = 1∙2 ∙ … ∙ 9∙10?

2.

Step-by-step explanation:

To find the number of trailing zeroes, given n!, we take n and divide it by increasing powers of 5. For example, the number of trailing zeroes in 50! = 50/5 = 10, 50/25 = 2, 10 + 2 = 12 trailing zeroes.

In this case, 10/5 = 2, and since we cannot get an integer from dividing 10 and 25, we are left with this answer.

I hope this helps!

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: