Find values of a. b. and c (if possible) such that the system of linear equations has a unique solution, no solution, and infinitely many solutions. (If not possible, enter IMPOSSIBLE.) X + y = 6
y + z = 6
x + z = 6
ax + by + cz = 0
a) a unique solution (a. b .c)=([])
b) no solution (a. b .c)=([])
c) infinitely many solutions (a. b, c) = ([])

Step-by-step explanation:

The given equations are

x + y = 6- - - - - - - - -1

y + z = 6- - - - - - - -2

x + z = 6- - - - - - - - - 3

From equation 2, y = 6 - z

Substituting y = 6 - z into equation 1, it becomes

x + 6 - z = 6

x - z = 6 - 6

x - z = 0

x = z

Substituting x = z into equation 3, it becomes

z + z = 6

2z = 6

z = 6/2

z = 3

x = 3

Substituting x = 3 into equation 1, it becomes

3 + y = 6

y = 6 - 3

y = 3

ax + by + cz = 0

3a + 3b + 3c = 0

3(a + b + c) = 0

Therefore, it is impossible

41*67/2=1373.5

step-by-step explanation:

i just used a calculator