Find the values of a and b that make the second expression equivalent to the first expression. Assume that x > 0 and y ≥ 0. StartRoot StartFraction 126 x y Superscript 5 Baseline Over 32 x cubed EndFraction EndRoot = StartRoot StartFraction 63 y Superscript 5 Baseline Over a x Superscript b Baseline EndFraction EndRoot a = and b =

What was done from the first to the second equation was that the fraction was simplified. 126 and 32 have a common factors of 2. 

126/32=(63*2)/(16*2)

The 2s in the top and bottom can cancel out, leaving the fraction 63/16. 

In addition, since there are x terms on the top and bottom, they cancelled out as well. 

x/x^3=1/x^2

This leaves an x^2 term on the bottom. 

Thus, if a is 16, and b is 2, you will have an equivalent form of the fraction.

Step-by-step explanation:

A=16 & B=2

Second part is B

Step-by-step explanation:

;)

linear pair postulates