10=0.0048(×_50)^2+6The cable is 10 feet above the roadway at horizontal distances of about 4ft and 96 ft. 13ft and 87ft. 21ft and 79 ft. 48ft and 52 ft from the left support

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Step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204