A histogram is being made for the following list of data. If the length of each interval is going to be 5, how many bars will there be on the histogram?
78, 92, 98, 87, 86, 72, 92, 81, 86, 92
04
05
06
07

Anyone know? will mark brainliest if correct

For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)

Use a standard normal table to determine the probability. give your answer as a decimal to four decimal places. −1.5< < 1.5)