A local maximum of the function f(x) occurs for which x-value? A 2-column table with 6 rows. The first column is labeled x with entries negative 4, negative 3, negative 2, negative 1, 0, 1. The second column is labeled f of x with entries 16, negative 2, 0, 6, 0, negative 2.

–4
–3
–2
–1

There is a local maximum at the point (-1,6), therefore, for x = -1

Step-by-step explanation:

Notice that the function adopts values smaller than 6 to the left of x = -1, and to the right of it:

(-3, -2), (-2, 0) to the left of x = -1 where the function's value is 6

and (0, 0), and (1, -2) to the right of x = -1

therefore, it looks like (-1, 6) is a maximum, that is for x = -1, where the function renders a value of 6.

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743