Terry bought some gum and some candy. The number of packs of chewing gum was one more than the number of mints. The number of mints was three times the number of chocolate bars. If gum cost 6 cents a pack, mints cost 3 cents each, and chocolate bars cost 10 cents each, how many of each confection did he get for 80 cents?

number of packs of chewing gum is 7

number of mints  is 6

number of chocolate bars is 2

Step-by-step explanation:

number of packs of chewing gum → x,  cost 6¢

number of mints → y = x-1 =3z,  cost  3¢

number of chocolate bars → z = y/3 = (x-1)/3, cost 10¢

put in equation 6x + 3y +10z = 80 plug in term of x

6x +3(x-1) +10((x-1)/3) =80 multiply each side by 3

18x +9(x-1) +10(x-1) =240 distribute

18x+9x-9+10x-10 =240 combine like terms

37x-19 = 240 add 19 in each side

37x =259

x = 7

plug into y = x-1 = 7-1 = 6 so y=6

and  z = y/3 =6/3 =2 so z = 2

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer