I NEED TO QUICKLY PLS HELP ME PPLLS AB, BE, and CF are all diameters of the circle. The measure of angle AOB is 40 degrees. The measure of angle DOF is 120 degrees.
Find the measure of angle COD. Find the measure of angle BOC.
Find the measure of angle COD

Angle COD is 60 degrees

angle BOC is 80 degrees

Because angle DOE is vertically opposite to angle boa, it is also 40 degrees. we know that angle DOF is 120, so angle FOE is 120-40 = 80 degree, and angle BOC is vertically opposite do it is 80 degrees.

since angle COD lies on a straight line it adds up to 180 degrees, so 180- 120 = 60 degrees

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step-by-step explanation:

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intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this