Which set of ordered pairs could be generated by an exponential function? A (-1, -1/2), (0,0), (1, 1/2), (2,1) B (-1,-1), (0,0), (1,1), (2,8) C (-1,1/2), (0,1), (1,2), (2,4) D (-1,1), (0,0), (1,1), (2,4)

there are no short passages to look at

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: