A trapezoid has an area of 20 cm2 and a height z cm. The lengths of the parallel sides are (2z + 3) cm and (6z – 1) cm. Find the height, z, of the trapezoid. In your final answer, include all of the formulas and calculations necessary.

2.11cm

Step-by-step explanation:

Given the following :

The lengths of the parallel sides are (2z + 3) cm and (6z – 1) cm

The area of trapezoid is calculated using the formula:

1/2(a + b) × h

Where ;

a = Length of side 1

b = length of side 2

h = height

Take a = (2z + 3) and b = (6z – 1), h = z

Therefore ;

1/2 (2z + 3 + 6z - 1) × z

Opening the bracket

(z + 1.5 + 3z - 0.5) × z

(4z + 1 ) × z = 20cm^2

4z^2 + z = 20cm^2

Using Quadratic formula:

4z^2 + z - 20 = 0

a = 4, b = 1, c = - 20

(-b±√b^2 -4ac) / 2a

Z = 2.11 or - 2.364

z cannot be negative, therefore,

Z = 2.11 cm

12.5 feet

step-by-step explanation:

step-by-step explanation:

one of the most important purposes of surface treatment is to alter surface properties according to the requirement of specific applications. for example, hydrophobic coating has been utilized on windshield and eyeglasses. gold atom monolayer on substrate has become a popular surface bioconjugation strategy.