Find points of discontinuity y=x^2+5x+6/x^2-16

  x=4 and x=-4

Step-by-step explanation:

We assume you intend ...

  y = (x^2 +5x +6)/(x^2 -16)

There will generally be points of discontinuity where the denominator is zero. Sometimes a denominator factor will be cancelled by a numerator factor, but the "hole" remains and there is still a discontinuity there.

Here, the denominator factors as the difference of squares:

  x^2 -16 = (x -4)(x +4)

There will be discontinuities where these factors are zero, at x=4 and x=-4.

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

the answer is 489

step-by-step explanation: