Justin ,cam and Ben are playing a board game where exactly one player will win .Ben estimates that Justin has a 20% chance of winning each game and that cam has a 50% chance of winning each game?

Question :

Justin, Cam, and Ben are playing a board game where exactly one player will win. Ben estimates that Justin has a 20%, percent chance of winning each game and that Cam has a 50%, percent chance of winning each game. What is the probability that Ben will win the board game?

30%

Step-by-step explanation:

Given the following :

Justin's chance of winning each game = 20%

Cam's chance of winning each game = 50%

Therefore, probability of :

Justin winning = 20/100 = 0.2

Cam winning = 50/100 = 0.5

Overall probability = 100% = 1

Therefore,

P(Justin winning) + P(Cam winning) + P(Ben winning) = 1

0.2 + 0.5 + P(Ben winning) = 1

P(Ben winning) = 1 - 0.7

P(Ben winning) = 0.3

0.3 = 30%

i used to know but i learned it a long time ago sorry

step-by-step explanation:

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step-by-step explanation: