A catapult launches a boulder with an upward velocity of 120 ft/s. The height of the boulder, h, in feet after t seconds is given by the function h = -16t^2 + 120t + 10. How long does it take to reach maximum height? What is the boulder's maximum height? What is the boulder's maximum height? Round to the nearest hundredth, if necessary.

See below in bold.

Step-by-step explanation:

h = -16t^2 + 120t + 10

To find the  height and time for maximum we convert to vertex form:

h = -16(t^2 - 7.5t) + 10

h = -16 [(t - 3.75)^2 - 14.0625] + 10

h = -16(t - 3.75)^2 + 225 + 10

h = -16(t - 3.75)^2 + 235

So the time to reach maximum height is 3.75 seconds and the maximum height = 235 ft.

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

b). 4320 have a nice day