The mean playing time for a large collection of compact discs is 34 minutes, and the standard deviation is 6 minutes. (a) What value (in minutes) is 1 standard deviation above the mean

40 minutes

Step-by-step explanation:

Let's take the average playing time as u, and let the standard deviation be .

Thus,

To find the value of 1 standard deviation above the mean, we have:

Since u = 34 minutes and = 6 minutes, we now have:

The value (in minutes) of 1 standard deviation above the mean is 40 minutes.

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles