I WILL MARK BRAINLIEST
look at attachment

see below

Step-by-step explanation:

h(t) = –gt^2 + v0t + h

where g is 1/2 the gravity constant and v0 is the initial velocity and h is the initial height

h(t) = –16t^2 +49t + 0

h(t) = –16t^2 +49t

Factor out t

0 = t(-16t+49)

The zeros are at

t= 0 and   -16t = -49

                      t = 49/16

The vertex  (or max) is 1/2 way between the zeros

(0+ 49/16)  /2 = 49/32  =1.53125

Round to the nearest hundredth

x = 1.53

The height is

h(1.53) = 1.53(-16 * 1.53 +49)

          37.5156

To the nearest hundredth

           37.52

The range is the values that height can take

0 ≤h≤37.52

There is a maximum height because eventually the effects of gravity going down outweigh the effects of the initial velocity going up

add 5 subtract 1

step-by-step explanation: