F(x) = x ^ 2 + 6x - 4 in vertex form

f(x) = (x + 3)² - 13

Step-by-step explanation:

The equation of a parabola in vertex form is

f(x) = a(x - h)² + k

Given

f(x) = x² + 6x - 4

Using the method of completing the square

add/subtract ( half the coefficient of the x- term )² to x² + 6x

f(x) = x² + 2(3)x + 9 - 9 - 4

f(x) = (x + 3)² - 13 ← in vertex form

after simplifying it i got: -36.25 as my answer. hope that !

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1