Center is ![(-12,9)](/tpl/images/0678/9828/e8105.png)
Step-by-step explanation:
Given: Equation of a circle is ![(x+12)^2+(y-9)^2=35](/tpl/images/0678/9828/470a1.png)
To find: center of the circle
Solution:
A circle is a locus of all points which are at equidistant from the fixed point (center).
Equation of a circle is of form
where
represents center of the circle and r denotes radius of the circle.
Given equation is ![(x+12)^2+(y-9)^2=35](/tpl/images/0678/9828/470a1.png)
![\left [ x-(-12) \right ]^2+(y-9)^2=35](/tpl/images/0678/9828/8db88.png)
Compare this equation with ![(x-a)^2+(y-b)^2=r^2](/tpl/images/0678/9828/34f2d.png)
Center is ![(a,b)=(-12,9)](/tpl/images/0678/9828/0a1bf.png)