Scores of an IQ test have a bell-shaped distribution with a mean of 100 and a standard deviation of 20. Use the empirical rule to determine the followinWhat percentage of people has an IQ score greater than 120?

Percentage of people with IQ greater than 120 is 84.134%

Step-by-step explanation:

First thing we do here is to calculate the

z-score

Mathematically;

z-score = (x-mean)/SD

here, x = 120, mean = 100 while SD = standard deviation = 20

z-score = (120-100)/20 = 20/20 = 1

The probability we want to calculate is;

P(x > 120) or P(z >1)

we proceed to use the standard score table to get this;

From the standard score table ;

P(z >1) = 0.84134

which is in percentage = 84.134%

b

step-by-step explanation:

b

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1