Convert the following complex number into its polar representation: -40
O A. 4(6052isang
37
B. 2(cos(+ isin)
C. 16(COST* isin x)
O D. -4(cose i sin

The correct option is B. 3√2(cos(135°) + i·sin(135°))

Step-by-step explanation:

The complex number is given as : 3 - 3i

Now, comparing this with the standard for : a + bi

⇒ a = 3 and b = -3

Now, r = √a² + b²

⇒ r = √18

⇒ r = 3√2

Now, The polar form is represented by :

z = r(cosθ + i·sinθ)

⇒ z = 3√2(cos 135° + i·sin 135°)

Therefore, the correct option is B. 3√2(cos(135°) + i·sin(135°))

Step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.