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Mathematics, 05.06.2020 13:57 Zacwn6360

Solve sin^2 2θ=-1-cos^2θ on the interval 0<θ<2pi A. No solution
B. Infinitely many solutions
C. 0, 2pi/3, 4pi/3, 2pi
D. 2pi/3, 4pi/3


Solve sin^2 2θ=-1-cos^2θ on the interval 0<θ<2pi

A. No solution 
B. Infinitely many solutio

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Answers: 1

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Solve sin^2 2θ=-1-cos^2θ on the interval 0<θ<2pi A. No solution
B. Infinitely many sol...

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