Hallar el área y el perímetro de un rombo cuyas diagonales menor y mayor miden, respectivamente,10 cm y 24 cm

The area is 120 cm²

the perimeter is 52 cm

Step-by-step explanation:

The rhombus area is given by:

A = D * d / 2

that is, the larger diagonal D by the smaller diagonal d, between two, we know that D = 24 cm and d = 10 cm, replacing:

A = 24 * 10/2

A = 120

The area is 120 cm²

To calculate the perimeter use the Pythagorean theorem

h² = a² + b²

Since if you look at the rhombus it is formed by four right triangle we will take 1 of them with the following measures 5 cm (10/2) and height 12 cm (24/2) and replace:

h² = 5² + 12²

h² = 169

h = 13

now, the perimeter would be the sum of all its sides, which in this case are equal and measure 13 cm, therefore:

p = 4 * 13

p = 52

which means that the perimeter is 52 cm

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b

step-by-step explanation:

it have 5 sides and 5 identicle angle.the rest does not have the same property as b.

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