Identify each x-value at which the slope of the tangent line to the function f(x) = 0.2x2 + 5x − 12 belongs to the interval (-1, 1).

slope of the tangent

The slope of the tangent to the interval (-1 ,1)

m = 4.6 ,5, 5.4

Step-by-step explanation:

Step(i):-

Given function is  f(x) = 0.2 x² + 5 x − 12

Slope of the tangent formula

Let y =  f(x) = 0.2 x² + 5 x − 12 ...(i)

Differentiating equation(i) with respective to 'x' , we get

let x=-1

let x=0

m = 5

let x=1

conclusion:-

slope of the tangent

The slope of the tangent to the interval (-1 ,1)

m = 4.6 , 5,  5.4

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step-by-step explanation:

r = 78539458390583095803458309458039485093485 or just 3

step-by-step explanation: