Priya’s cat is pregnant with a litter of 5 kittens. Each kitten has a 30% chance of being chocolate brown. Priya wants to know the probability that at least two of the kittens

will be chocolate brown.

To simulate this, Priya put 3 white cubes and 7 green cubes in a bag. For each trial,

Priya pulled out and returned a cube 5 times. Priya conducted 12 trials.

30.87%

Step-by-step explanation:

Priya's simulation is fine, as 30% is represented by the 3 white cubes.

The more times the experiment is carried out, the closer it is to the theoretical probability, which is calculated as follows:

p (n = x) = nCx * p ^ x * q ^ (n-x)

We obtain that p = 0.3 and q = 1-0.3 = 0.7. also n = 5 and x = 2.

replacing we have:

p (5 = 2) = 5C2 * 0.3 ^ 2 * 0.7 ^ (5-2)

p (5 = 2) = 5! / (2! * 3!) * 0.03087

p (5 = 2) = 0.3087

which means that the probability is 30.87%, and the more the experiment is carried out, the closer it is to this probability.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine