Suppose a horse is galloping at 19 mph toward a clown, and the clown is racing toward the horse on an ATV which can sustain a speed of 15mph. They are 50 miles apart from one another and start at the exact same moment in time. How much time will it take for the horse and clown to collide?

It will take 1.47 hours for the horse and clown to collide

Step-by-step explanation:

They are driving toward each other, in opposite directions.

So to find their speed of approximation, we add their speeds.

19 mph + 15 mph = 34 mph.

This means that each hour, they are 34 miles closer.

How long it takes for them to find each other if they are 50 miles apart?

1 hour - 34 miles

x hours - 50 miles

It will take 1.47 hours for the horse and clown to collide

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.