The box plots show the average speeds, in miles per hour, for the race cars in two different races. Average Speeds of Cars in Race A 2 box plots. The number line goes from 120 to 170. For Race A, the whiskers range from 120 to 170, and the box ranges from 143 to 165. A line divides the box at 153. For Race B, the whiskers range from 125 to 165, and the box ranges from 140 to 150. A line divides the box at 145. Average Speeds of Cars in Race B Which correctly describes the consistency of the speeds of the cars in the two races? The speeds in race A are likely to be near 170 mph and the speeds in race B are likely to be near to 165 mph. The speeds in race A are likely to be near 153 mph and the speeds in race B are likely to be near to 145 mph. The speeds in race A are likely to be near 120 mph and the speeds in race B are likely to be near to 125 mph. The speeds in race A are likely to be near 145 mph and the speeds in race B are likely to be near to 153 mph.

At a lunchron, guests are offered a selection of five different grilled vegetables and four different meats. in how many waya could one choose three vegetables and two meats?

The border line of the linear inequality 4x + 7y < 5 is dotted true or false?

Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.