The depth of water at the end of a pier varies with the tides. The low tides occur on a particular day at 2:00 a. m. and 2:00 p. m. with a depth of 1.1 m. The high tides occur at 8:00 a. m. and 8:00 p. m. with a depth of 5.3 m. A large boat needs at least 3 m of water to be safely secured at the end of the pier. What is the first time in the morning that is it safe for the boat to be tied to the pier

4:42 a.m.

Step-by-step explanation:

The earliest low tide occurs by 2:00 a.m. and the earliest high tide occurs by 8:00 a.m.

Between these hours, 6 hours elapsed.

The lowest point is 1.1 m and increases steadily to 5.3 m.

Let us take 2:00 a.m. as the zeroth hour, and 8:00 a.m. as the 6th hour, we can safely interpolate as below,

0 = 1.1 m

x = 3 m

6 = 5.3 m

we solve as =

=

4.2x = 11.4

x = 2.71 hours from 2:00 a.m.

= 2 hrs + (0.71 x 60)min = 2 hrs 42.6 min

the time will approximately be by 4:42 a.m.

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560