Type the correct answer in each box. Use numerals instead of words. Consider this quadratic equation. x2 + 2x + 7 = 21

Complete question is;

Type the correct answer in each box. Use numerals instead of words. Consider this quadratic equation. x² + 2x + 7 = 21 The number of positive solutions to this equation is . The approximate value of the greatest solution to the equation, rounded to the nearest hundredth, is

The approximate value of the greatest solution to the equation, rounded to the nearest hundredth, is 2.87.

Step-by-step explanation:

We are given the quadratic equation as;

x² + 2x + 7 = 21

Subtract 21 from both sides to give ;

x² + 2x + 7 - 21 = 0

x² + 2x - 14 = 0

Using quadratic formula, we cam find the roots of the equation.

x = [-b ± √b² - 4ac]/2a

Plugging in the values;

x = [-2 ± √(2² - 4(1*-14))]/2(1)

x = [-2 ± √(4 + 56)]/2

x = [-2 ± √60]/2

x = - 4.87 or 2.87

Thus, this equation has only one positive solution which is the greatest.

Thus, greatest solution is 2.87

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).

well if he bought them at 5 cedis each sold them at 7 cedis each then he would make a profit of 2 cedis of each book. if in total he made 150 cedis profit that means he sold 75 books. he lost 12 books at the start so that means he originally bought a total of 82 books.

step-by-step explanation: