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He has 7 nickels, 14 dimes, and 21 quarters.

Step-by-step explanation:

Let d = number of dimes.

Let n = number of nickels.

Let q = number of quarters.

The value of a dime is $0.10, so d dimes are worth 0.1d

The value of a nickel is $0.05, so n nickles are worth 0.05n

The value of a quarter is $0.25, so q quarters are worth 0.25q

The value of all coins combined is the sum of the values above, and it equals $7.00

0.1d + 0.05n + 0.25q = 7

The number of dimes = 2 times the number of nickels, so

d = 2n

The number of quarters = 3 times the number of nickels, so

q = 3n

Now we substitute 2n for d and 3n for q in our equation above.

0.1d + 0.05n + 0.25q = 7

0.1(2n) + 0.05n + 0.25(3n) = 7

0.2n + 0.05n + 0.75n = 7

n = 7

He has 7 nickels.

d = 2n = 2(7) = 14

He has 14 dimes.

q = 3n = 3(7) = 21

He has 21 quarters.

He has 7 nickels, 14 dimes, and 21 quarters.

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step-by-step explanation:

should you really be posting this isn't math boi.