Please help! You pick a card at random. Without putting the first card back, you pick a second card at random. What is the probability of picking an even number and then picking an even number?

Simplify your answer and write it as a fraction or whole number.

5/6

Step-by-step explanation:

2/4 the first time you pick then 1/3 the second time

the total amount of cards is 4

then you count how many even numbers there are and that over 4 is the probability of picking even numbers on the first try  (2/4)=answer part 1

then after you take a even card out the total becomes 3 so you then count again how many even cards are left and you put that over 3 so the second part of the answer would be 1/3

the you add the 2 probabilitys together to get 5/6 as the answer

answer: 40.95

step-by-step explanation:

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer