Luiza is jumping on a trampoline. H(t)H(t)
H(t)
H, left parenthesis, t, right parenthesis
models her distance above the ground (in
m\text{m}
m
start text, m, end text
)
tt
t
t
seconds after she starts jumping. Here,
tt
t
t
is entered in radians.
H(t)=−0.6cos⁡(2π2.5t)+1.5H(t) = -0.6\cos\left(\dfrac{2\pi}{2.5}t\ri ght) + 1.5
H(t)=−0.6cos(
2.5

2π


t)+1.5
H, left parenthesis, t, right parenthesis, equals, minus, 0, point, 6, cosine, left parenthesis, start fraction, 2, pi, divided by, 2, point, 5, end fraction, t, right parenthesis, plus, 1, point, 5
What is the second time when Luiza reaches a height of
1.2 m1.2\text{ m}
1.2 m
1, point, 2, start text, space, m, end text
?
Round your final answer to the nearest hundredth of a second.

a, b, c, d are correct.

step-by-step explanation:

we have g(x) = 3 and are required to find which option is a translation of g(x).

now, 'translation' is a transformation which means to shift the function in any direction and the general form of translation is g(x) + k, where k is any real number.

so, according to the options we see that all are correct as they satisfy the general form of translation.

also, it can be seen from the graph below that the function g(x) = 3 is shifted from its position in all the four options.

$649.60

step-by-step explanation:

arc length = 6.63311 ft.

step-by-step explanation:

the formula the arc measure is:

arc length s=2πr(c)/360

where:

c   is the central angle of the arc in degrees

r   is the radius of the arc

π   is pi, approximately 3.142

using the above formula we get

s =

thus we find that arc length of an arc for a circle of radius 20 feet and central angle 19 degrees is

6.63311 feet