Kayson is looking at two buildings, building A and building B, at an angle of elevation of 40' Building Als 120 feet away, and building B is 60 feet away which building is taller and by approximately how many feet? Building A It is around 100 69 feet taller than building B
Building A it is around 50 34 feet taller than building B
O Building B, it is around 100.69 feet taller than building A
Building B, it is around 50.34 feet taller than building A

A. Building A, it is around 100.69 feet taller than building B.

Step-by-step explanation:

Since building A is 120 feet away at and elevation of , then:

Tan =

Where x is the height of the building at the horizontal plane.

x = Tan   × 120

   = 100.692 feet

For building B at the same elevation,

Tan   =

 x = Tan   × 60

    = 50.346 feet

Since the angle of elevation are the same, building A is around 100.69 feet taller than building B.

i have no clue at all sorry

step-by-step explanation:

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: