A Fair coin is tossed 4 times. What is the probability of not getting all heads?

15/16

Step-by-step explanation:

The probability of not getting all heads is

1 - P(all heads)

P (all heads) =P(heads) *  P(heads)* P(heads) * P(heads)

                      1/2* 1/2 * 1/2 * 1/2 = 1/16

1 - 1//16 = 15/16

∞ this is your sign

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )