Ed is constructing the perpendicular bisector of a segment on his paper. He just finished labeling the points of intersection of the two arcs that he drew. What is his next step?

The next step is to draw a line connecting the two labelled points, that is from one side of the line to be bisected to the other

The line drawn in the above step, from the two labelled points is the perpendicular bisector of the segment

Step-by-step explanation:

To draw a perpendicular bisector of a segment, we have;

1. Ensure the compass is opened to more than half of the length of the segment to be bisected

2. Draw arcs of the same radius with center at the ends of the line to be bisected

3. Label the points where the arcs drawn from both ends cross each other on opposite sides of the line

4. Draw a line connecting the two labelled points, that is from one side of the line to be bisected to the other

5. The line so drawn from the two labelled points is the perpendicular bisector of the segment.

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

i need on these three questions. find standard form equation of line perpendicular to y = (2/3)x - 8 that goes through the point

the equation of a line is -6x-2y=-18 what is the x 3 answers sep 21, 2015

finding the critical point for f(x,y)=(x^2)*y+y^3 1 answer mar 10, 2013

more results from answers.yahoo.com

step-by-step explanation: