Missing side = 2
X= 2
Have given details if x was only base of the side triangle
This is in order to find a completely new triangle with just the height and in order to find and combine 1 given area say if just the right side in your diagram was 4 and we had to find the other triangle. This is only done on scale or 1 given measure or angle for the right side triangle. We was not given this but proved a 0.3 scale.
Area of other triangle =2.66^2
2.66+4 combined = 6.66^2
Step-by-step explanation:
We find a square height is also 4
We also know a right angle triangles height can be found using either 1/2 base or 1/2 height.
So this can mean the height is and stays 4 and the base is 2.
As 1/2 4 height = 2 height
2 unit height x 2 unit base = 4
Therefore, the first triangle slant is the same.
4sq +2sq = c^2
√16+√4 = √20
c^2 = √20 = 4.47 = 4.472135955
c = 4.47 slant
Given a=4 and c=4.47,
b = 1.99522
∠α = 63.49° = 63°29'23"
∠β = 26.51° = 26°30'37"
h = 1.78543
We cna tell now that the triangle is 0.333 smaller so the measurements
Show 2/3 of 2 = 1.333 being the base across
using this as Area we find 1.333 x 2 = 2.666
(1/2 h^b of 4) =2
We can prove with the angles
63 +27 degree or
a^2+b^2 = c^2
1.333^2 + 4^2
= √1.776889+√ 16 = √ 17.776889
c^2 = 4.21626481616
c= 4.22 slant left side (nb right side on attachment)
Angle ∠ A = α = 71.478° = 71°28'39″
Angle ∠ B = β = 63.53° = 63°31'48″
Angle ∠ C = γ = 44.992° = 44°59'33″
We see 63 angle on right lower side of attachment picture in reflection and can prove x = 3.333
But on your diagram base x = 2
What i have done is enlarged x by 0.3 and proven how to find x if x was just one side of the triangle's height.
The triangles even though reflected are identical.
Other info is proven through finding ha and hb heights.
We confirm 4.001 is the hc height of your diagram.
Height: ha = 2.984
Height: hb = 3.16
Height: hc = 4.001
