The radius of Circle Upper A is 5 in. The radius of Circle Upper B is 5 in. greater than the radius of Circle Upper A. The radius of Circle Upper C is 2 in. greater than the radius of Circle Upper B. The radius of Circle Upper D is 3 in. less than the radius of Circle Upper C. What is the area of each circle? How many times greater than the area of Circle Upper A is the area of Circle Upper D?

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

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step-by-step explanation:

save it by not spending on unnecessary stuff and have more

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

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step-by-step explanation: