Mathematics, 03.06.2020 14:57 adejumoayobami1
Since JKLM is a rhombus, JM ≅ LM and JK ≅ LK. MK ≅ MK by the Reflexive Property of Congruence. So, △MJK ≅ △MLK by the Triangle Congruence Theorem. Therefore, ∠JMK ≅ ∠ and ∠JKM ≅ ∠ by CPCTC, so MK bisects ∠JML and ∠JKL. A similar argument shows that JL bisects ∠MJK and ∠MLK.
Prove that if a parallelogram is a rhombus, then each diagonal bisects a pair of opposite angles. Complete the proof.
Given: JKLM is a rhombus.
Prove: MK bisects ∠JML and ∠JKL; JL bisects ∠MJK and ∠MLK
Answers: 1
Mathematics, 21.06.2019 15:10, sbelgirl2000
Figure abcde is a regular pentagon. segment ae is located at a (2, 1) and e (4, 1). what is the perimeter of abcde? 4 units 6 units 8 units 10 units
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Mathematics, 21.06.2019 20:00, haleysmith8608
Given the graphed function below which of the following orders pairs are found on the inverse function
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Since JKLM is a rhombus, JM ≅ LM and JK ≅ LK. MK ≅ MK by the Reflexive Property of Congruence. So, △...
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