Parallelogram ABCD has vertices at A(0, 0) , B(3, 6) , C(5, 5) , and D(2,−1) . Which conclusion can be made? AC=BD; therefore, ABCD is a rhombus. AC¯¯¯¯¯⊥BD¯¯¯¯¯; therefore, ABCD is a rhombus. AC=BD; therefore, ABCD is a rectangle. AC¯¯¯¯¯⊥BD¯¯¯¯¯; therefore, ABCD is a rectangle.

Answer I got:

Asequence has its first term equal to 4, and each term of the sequence is obtained by adding 2 to the previous term. if f(n) represents the nth term of the sequence, which of the following recursive functions best defines this sequence? (1 point) f(1) = 2 and f(n) = f(n − 1) + 4; n > 1 f(1) = 4 and f(n) = f(n − 1) + 2n; n > 1 f(1) = 2 and f(n) = f(n − 1) + 4n; n > 1 f(1) = 4 and f(n) = f(n − 1) + 2; n > 1 i will award !