A new automobile is purchased for $20,000. If V = 2,000(0.8) x , gives the car's value after x years, about how long will it take for the car to be worth $820?

It will take 4 years

Step-by-step explanation:

Here, given the exponential equation that approximates the cost of a car after a certain amount of time, we are tasked with calculating the amount of time it will take to be worth a certain amount.

The exponential equation that approximates the cost of the car is given as;

V = 2,000(0.8)^x

Now, our V = 820 but we want to calculate x which gives the number of years. Substituting this value of V, we get;

820 = 2000(0.8)^x

divide through by 2000

0.41 = 0.8^x

Take the log of both sides

log 0.41 = log 0.8^x

log 0.41 = xlog 0.8

x = log 0.41/log 0.8

x = 3.99 which is approximately 4 years

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

the correct answer is semicircle

step-by-step explanation:

the answer is semicircle because the shorter arc joining two points on the circumference of a circle is known as the minor arc, the larger arc is called the major arc, and a semicircle is a half circle, formed by cutting a whole circle along a diameter line.

hope i .