Difference of squares: What is x^2-9=0?
please help me

3 or -3

Step-by-step explanation:

You need to factor it to be able to find the solution.

x^2-9=0

(x+3)(x-3)=0  You now need to find 'each' zero, because if one parenthesis equals 0, then you are multiplying the rest of the equation by 0 which will equal 0.

x+3=0  Subtract three

x= -3    

x-3=0  Add three

x= 3

x^2-9 will equal 0 when x is either +3 or -3

x=3  x=-3

Step-by-step explanation:

x^2-9=0

We know this is the difference of squares

a^2 - b^2 = (a-b) (a+b)

(x-3)(x+3) =0

Using the zero product property

x-3 =0  x+3 =0

x=3  x=-3

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

x=6 and x=3

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