A bus company recorded the ages, in years, of the people on coach A and the people
on coach B.
Here are the ages of the 23 people on coach A.
41 42 44 48 52 53 53 53 56 57 57 59
60 61 63 64 64 66 67 69 74 77 79
(a) Complete the table below to show information about the ages of the people on coach A.

Median : 59

Lower quartile : 53

Upper quartile : 66

Least age: 41

Greatest age:  79

Step-by-step explanation:

In a ordered list, the median is the number at the half position. With 23 numbers, the half position the 12th number (there are 11 number above and blow it)

41 42 44 48 52 53 53 53 56 57 57 59  60 61 63 64 64 66 67 69 74 77 79

The lower quartile  is the number at the half position, only considering the first data points until the median.

41 42 44 48 52 53 53 53 56 57 57

The upper quartile  is the number at the half position, only considering the data points after the median.

60 61 63 64 64 66 67 69 74 77 79

The least and greatest ages are easily found.

Step-by-step explanation:

median = 58

lower quartile = 53

upper quartile = 66

leastest age = 40

greatest age = 82

9 x 8 divided by (5-3)=36

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb