Brandon is an amateur marksman. When he takes aim at a particular target on the shooting range, there is a 0.10.10, point, 1 probability that he will hit it. One day, Brandon decides to attempt to hit 101010 such targets in a row.
Assuming that Brandon is equally likely to hit each of the 101010 targets, what is the probability that he will hit at least one of them?
Round your answer to the nearest hundredth.

.65

Step-by-step explanation:

In this situation it is much easier to calculate the probability of the event we are looking for (he hits at least one target) by calculating the probability of its complement (he misses every target), and subtracting from 1.

In other words, we can use this strategy:

P(at least one hit)=1-P(miss all 10)

Calculations:

P(at least one hit)

=1-P(miss all 10)

=1-(0.9)^10

≈1-0.349

≈0.65

P(at least one hit)≈0.65

I hope this helps!!!

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

[2, 2.5)

(2.5, 3]

step-by-step explanation:

i think its these two not sure [2, 2.5)

(2.5, 3]