A function g(x) has x-intercepts at (5,0) and (6, 0). Which could be g(x)?
g(x) = 2(x + 1)(x + 6)
g(x) = (x + 6) (2x - 1)
g(x) = 2(x-2)(x-6)
g(x) = (x + 6) (x + 2)

g(x) = a(x-5) ( x-6)

Step-by-step explanation:

A function g(x) has x-intercepts at (5,0) and (6, 0)

g(x) = a(x-5) ( x-6)

If you mistyped and the x intercepts are at 2 and 6

g(x) = 2(x-2)(x-6)

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

the answer is: -22 also a

hope i

-lavira: )